140131320211411 has 2 divisors, whose sum is σ = 140131320211412. Its totient is φ = 140131320211410.

The previous prime is 140131320211361. The next prime is 140131320211457. The reversal of 140131320211411 is 114112023131041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140131320211411 - 2¹³ = 140131320203219 is a prime.

It is a super-2 number, since 2×140131320211411² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140131320211481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70065660105705 + 70065660105706.

It is an arithmetic number, because the mean of its divisors is an integer number (70065660105706).

Almost surely, 2^{140131320211411} is an apocalyptic number.

140131320211411 is a deficient number, since it is larger than the sum of its proper divisors (1).

140131320211411 is an equidigital number, since it uses as much as digits as its factorization.

140131320211411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 140131320211411 its reverse (114112023131041), we get a palindrome (254243343342452).

The spelling of 140131320211411 in words is "one hundred forty trillion, one hundred thirty-one billion, three hundred twenty million, two hundred eleven thousand, four hundred eleven".