1401325537 has 2 divisors, whose sum is σ = 1401325538. Its totient is φ = 1401325536.

The previous prime is 1401325469. The next prime is 1401325547. The reversal of 1401325537 is 7355231041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1290318241 + 111007296 = 35921^2 + 10536^2 .

It is an emirp because it is prime and its reverse (7355231041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1401325537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1401325499 and 1401325508.

It is not a weakly prime, because it can be changed into another prime (1401325547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700662768 + 700662769.

It is an arithmetic number, because the mean of its divisors is an integer number (700662769).

Almost surely, 2^1401325537 is an apocalyptic number.

It is an amenable number.

1401325537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401325537 is an equidigital number, since it uses as much as digits as its factorization.

1401325537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12600, while the sum is 31.

The square root of 1401325537 is about 37434.2829101881. The cubic root of 1401325537 is about 1119.0418934701.

Adding to 1401325537 its reverse (7355231041), we get a palindrome (8756556578).

The spelling of 1401325537 in words is "one billion, four hundred one million, three hundred twenty-five thousand, five hundred thirty-seven".