Base | Representation |
---|---|
bin | 1100101111101011101110… |
… | …1111111011001011010111 |
3 | 1211121122212021201211000101 |
4 | 3023322323233323023113 |
5 | 3314043301301101403 |
6 | 45445345244154531 |
7 | 2644300314023155 |
oct | 313727357731327 |
9 | 54548767654011 |
10 | 14013333222103 |
11 | 4513026305806 |
12 | 16a3a64b38a47 |
13 | 7a85b4386197 |
14 | 36636b1783d5 |
15 | 1947bb72271d |
hex | cbebbbfb2d7 |
14013333222103 has 2 divisors, whose sum is σ = 14013333222104. Its totient is φ = 14013333222102.
The previous prime is 14013333222089. The next prime is 14013333222137. The reversal of 14013333222103 is 30122233331041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14013333222103 - 217 = 14013333091031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14013333222173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006666611051 + 7006666611052.
It is an arithmetic number, because the mean of its divisors is an integer number (7006666611052).
Almost surely, 214013333222103 is an apocalyptic number.
14013333222103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14013333222103 is an equidigital number, since it uses as much as digits as its factorization.
14013333222103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 14013333222103 its reverse (30122233331041), we get a palindrome (44135566553144).
The spelling of 14013333222103 in words is "fourteen trillion, thirteen billion, three hundred thirty-three million, two hundred twenty-two thousand, one hundred three".
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