Base | Representation |
---|---|
bin | 10100011001001010110… |
… | …011011101101011101011 |
3 | 11221222021222022212212212 |
4 | 110121022303131223223 |
5 | 140430044032442103 |
6 | 2551444552555335 |
7 | 203151232242134 |
oct | 24311263355353 |
9 | 4858258285785 |
10 | 1401414343403 |
11 | 4a0377953438 |
12 | 1a772a9b2b4b |
13 | a21ca938169 |
14 | 4bb863b2c8b |
15 | 266c23d97d8 |
hex | 1464acddaeb |
1401414343403 has 2 divisors, whose sum is σ = 1401414343404. Its totient is φ = 1401414343402.
The previous prime is 1401414343337. The next prime is 1401414343411. The reversal of 1401414343403 is 3043434141041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1401414343403 - 212 = 1401414339307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1401414343403.
It is not a weakly prime, because it can be changed into another prime (1401414343423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700707171701 + 700707171702.
It is an arithmetic number, because the mean of its divisors is an integer number (700707171702).
Almost surely, 21401414343403 is an apocalyptic number.
1401414343403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401414343403 is an equidigital number, since it uses as much as digits as its factorization.
1401414343403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 1401414343403 its reverse (3043434141041), we get a palindrome (4444848484444).
The spelling of 1401414343403 in words is "one trillion, four hundred one billion, four hundred fourteen million, three hundred forty-three thousand, four hundred three".
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