Base | Representation |
---|---|
bin | 11111110111010100111110… |
… | …001101001101100101111011 |
3 | 200101012101210021211022220002 |
4 | 133313110332031031211323 |
5 | 121332034324034131443 |
6 | 1214020044131223215 |
7 | 41342614536444653 |
oct | 3767247615154573 |
9 | 611171707738802 |
10 | 140141531552123 |
11 | 40720765096142 |
12 | 1387444b447b0b |
13 | 602739c69124a |
14 | 2686c5a0b3363 |
15 | 11306098db2b8 |
hex | 7f753e34d97b |
140141531552123 has 2 divisors, whose sum is σ = 140141531552124. Its totient is φ = 140141531552122.
The previous prime is 140141531552111. The next prime is 140141531552251. The reversal of 140141531552123 is 321255135141041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140141531552123 - 26 = 140141531552059 is a prime.
It is not a weakly prime, because it can be changed into another prime (140141531572123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70070765776061 + 70070765776062.
It is an arithmetic number, because the mean of its divisors is an integer number (70070765776062).
Almost surely, 2140141531552123 is an apocalyptic number.
140141531552123 is a deficient number, since it is larger than the sum of its proper divisors (1).
140141531552123 is an equidigital number, since it uses as much as digits as its factorization.
140141531552123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 38.
Adding to 140141531552123 its reverse (321255135141041), we get a palindrome (461396666693164).
The spelling of 140141531552123 in words is "one hundred forty trillion, one hundred forty-one billion, five hundred thirty-one million, five hundred fifty-two thousand, one hundred twenty-three".
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