14014544000021 has 2 divisors, whose sum is σ = 14014544000022. Its totient is φ = 14014544000020.

The previous prime is 14014543999991. The next prime is 14014544000033. The reversal of 14014544000021 is 12000044541041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11798572359025 + 2215971640996 = 3434905^2 + 1488614^2 .

It is a cyclic number.

It is not a de Polignac number, because 14014544000021 - 2⁶ = 14014543999957 is a prime.

It is a super-2 number, since 2×14014544000021² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14014544000921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7007272000010 + 7007272000011.

It is an arithmetic number, because the mean of its divisors is an integer number (7007272000011).

Almost surely, 2^{14014544000021} is an apocalyptic number.

It is an amenable number.

14014544000021 is a deficient number, since it is larger than the sum of its proper divisors (1).

14014544000021 is an equidigital number, since it uses as much as digits as its factorization.

14014544000021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2560, while the sum is 26.

Adding to 14014544000021 its reverse (12000044541041), we get a palindrome (26014588541062).

The spelling of 14014544000021 in words is "fourteen trillion, fourteen billion, five hundred forty-four million, twenty-one", and thus it is an aban number.