Base | Representation |
---|---|
bin | 10100011001010001001… |
… | …011001000111011110011 |
3 | 11221222120102102102122102 |
4 | 110121101023020323303 |
5 | 140430303412310141 |
6 | 2551503331331015 |
7 | 203154000515612 |
oct | 24312113107363 |
9 | 4858512372572 |
10 | 1401521213171 |
11 | 4a0422207262 |
12 | 1a775a750a6b |
13 | a2216b15801 |
14 | 4bb96671879 |
15 | 266cb99999b |
hex | 146512c8ef3 |
1401521213171 has 2 divisors, whose sum is σ = 1401521213172. Its totient is φ = 1401521213170.
The previous prime is 1401521213153. The next prime is 1401521213177. The reversal of 1401521213171 is 1713121251041.
It is a strong prime.
It is an emirp because it is prime and its reverse (1713121251041) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1401521213171 is a prime.
It is not a weakly prime, because it can be changed into another prime (1401521213177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700760606585 + 700760606586.
It is an arithmetic number, because the mean of its divisors is an integer number (700760606586).
Almost surely, 21401521213171 is an apocalyptic number.
1401521213171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401521213171 is an equidigital number, since it uses as much as digits as its factorization.
1401521213171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1680, while the sum is 29.
The spelling of 1401521213171 in words is "one trillion, four hundred one billion, five hundred twenty-one million, two hundred thirteen thousand, one hundred seventy-one".
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