Base | Representation |
---|---|
bin | 10100011001010001001… |
… | …011001000111011100001 |
3 | 11221222120102102102121202 |
4 | 110121101023020323201 |
5 | 140430303412310103 |
6 | 2551503331330545 |
7 | 203154000515555 |
oct | 24312113107341 |
9 | 4858512372552 |
10 | 1401521213153 |
11 | 4a0422207246 |
12 | 1a775a750a55 |
13 | a2216b157b9 |
14 | 4bb96671865 |
15 | 266cb999988 |
hex | 146512c8ee1 |
1401521213153 has 2 divisors, whose sum is σ = 1401521213154. Its totient is φ = 1401521213152.
The previous prime is 1401521213119. The next prime is 1401521213171. The reversal of 1401521213153 is 3513121251041.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1107402638224 + 294118574929 = 1052332^2 + 542327^2 .
It is a cyclic number.
It is not a de Polignac number, because 1401521213153 - 210 = 1401521212129 is a prime.
It is not a weakly prime, because it can be changed into another prime (1401521203153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700760606576 + 700760606577.
It is an arithmetic number, because the mean of its divisors is an integer number (700760606577).
Almost surely, 21401521213153 is an apocalyptic number.
It is an amenable number.
1401521213153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401521213153 is an equidigital number, since it uses as much as digits as its factorization.
1401521213153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 1401521213153 its reverse (3513121251041), we get a palindrome (4914642464194).
The spelling of 1401521213153 in words is "one trillion, four hundred one billion, five hundred twenty-one million, two hundred thirteen thousand, one hundred fifty-three".
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