Base | Representation |
---|---|
bin | 11111110111011111101001… |
… | …110011001010111011111010 |
3 | 200101020111101120101011220110 |
4 | 133313133221303022323322 |
5 | 121332231321041404432 |
6 | 1214025222143205150 |
7 | 41343502000523640 |
oct | 3767375163127372 |
9 | 611214346334813 |
10 | 140153000341242 |
11 | 4072560aa03159 |
12 | 138767102a67b6 |
13 | 60284a97637b5 |
14 | 2687627333190 |
15 | 1130a7b6cadcc |
hex | 7f77e9ccaefa |
140153000341242 has 64 divisors (see below), whose sum is σ = 320758597601280. Its totient is φ = 39992610043584.
The previous prime is 140153000341219. The next prime is 140153000341261. The reversal of 140153000341242 is 242143000351041.
It is a super-2 number, since 2×1401530003412422 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 607520388 + ... + 607751040.
It is an arithmetic number, because the mean of its divisors is an integer number (5011853087520).
Almost surely, 2140153000341242 is an apocalyptic number.
140153000341242 is an abundant number, since it is smaller than the sum of its proper divisors (180605597260038).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140153000341242 is a wasteful number, since it uses less digits than its factorization.
140153000341242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 249067.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 140153000341242 its reverse (242143000351041), we get a palindrome (382296000692283).
The spelling of 140153000341242 in words is "one hundred forty trillion, one hundred fifty-three billion, three hundred forty-one thousand, two hundred forty-two".
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