Search a number
-
+
140155541013253 is a prime number
BaseRepresentation
bin11111110111100010000001…
…001111000100001100000101
3200101020201221122002200200211
4133313202001033010030011
5121332302021444411003
61214030322222435421
741343621651056653
oct3767420117041405
9611221848080624
10140155541013253
11407266a4066697
12138770bb132b71
1360287c2c3360c
1426877c892ddd3
151130b7978c96d
hex7f78813c4305

140155541013253 has 2 divisors, whose sum is σ = 140155541013254. Its totient is φ = 140155541013252.

The previous prime is 140155541013209. The next prime is 140155541013311. The reversal of 140155541013253 is 352310145551041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85267623998209 + 54887917015044 = 9234047^2 + 7408638^2 .

It is a cyclic number.

It is not a de Polignac number, because 140155541013253 - 233 = 140146951078661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140155541017253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70077770506626 + 70077770506627.

It is an arithmetic number, because the mean of its divisors is an integer number (70077770506627).

Almost surely, 2140155541013253 is an apocalyptic number.

It is an amenable number.

140155541013253 is a deficient number, since it is larger than the sum of its proper divisors (1).

140155541013253 is an equidigital number, since it uses as much as digits as its factorization.

140155541013253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 40.

Adding to 140155541013253 its reverse (352310145551041), we get a palindrome (492465686564294).

The spelling of 140155541013253 in words is "one hundred forty trillion, one hundred fifty-five billion, five hundred forty-one million, thirteen thousand, two hundred fifty-three".