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14017200851543 is a prime number
BaseRepresentation
bin1100101111111010001001…
…0001110000101001010111
31211122000211211100202012012
43023332202101300221113
53314124211404222133
645451225125014435
72644465206233561
oct313764221605127
954560754322165
1014017200851543
1145147304a8a7a
1216a476425441b
137a8a7c73c106
14366616ab2331
1519494604bb48
hexcbfa2470a57

14017200851543 has 2 divisors, whose sum is σ = 14017200851544. Its totient is φ = 14017200851542.

The previous prime is 14017200851501. The next prime is 14017200851557. The reversal of 14017200851543 is 34515800271041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14017200851543 - 210 = 14017200850519 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14017200851543.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14017200851243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7008600425771 + 7008600425772.

It is an arithmetic number, because the mean of its divisors is an integer number (7008600425772).

Almost surely, 214017200851543 is an apocalyptic number.

14017200851543 is a deficient number, since it is larger than the sum of its proper divisors (1).

14017200851543 is an equidigital number, since it uses as much as digits as its factorization.

14017200851543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 41.

The spelling of 14017200851543 in words is "fourteen trillion, seventeen billion, two hundred million, eight hundred fifty-one thousand, five hundred forty-three".