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1402001516213 is a prime number
BaseRepresentation
bin10100011001101101110…
…011010110011010110101
311222000210220012100112222
4110121231303112122311
5140432244342004323
62552023130052125
7203201622155204
oct24315563263265
94860726170488
101402001516213
114a0649340021
121a787357a045
13a22924923ac
144bc0037b23b
1526708c219c8
hex1466dcd66b5

1402001516213 has 2 divisors, whose sum is σ = 1402001516214. Its totient is φ = 1402001516212.

The previous prime is 1402001516141. The next prime is 1402001516221. The reversal of 1402001516213 is 3126151002041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1370531465809 + 31470050404 = 1170697^2 + 177398^2 .

It is a cyclic number.

It is not a de Polignac number, because 1402001516213 - 216 = 1402001450677 is a prime.

It is a super-2 number, since 2×14020015162132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1402001516233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701000758106 + 701000758107.

It is an arithmetic number, because the mean of its divisors is an integer number (701000758107).

Almost surely, 21402001516213 is an apocalyptic number.

It is an amenable number.

1402001516213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402001516213 is an equidigital number, since it uses as much as digits as its factorization.

1402001516213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 1402001516213 its reverse (3126151002041), we get a palindrome (4528152518254).

The spelling of 1402001516213 in words is "one trillion, four hundred two billion, one million, five hundred sixteen thousand, two hundred thirteen".