Search a number
-
+
1402013114 = 2701006557
BaseRepresentation
bin101001110010001…
…0000010110111010
310121201010122102122
41103210100112322
510332403404424
6351042001242
746512625535
oct12344202672
93551118378
101402013114
1165a444227
12331646222
13194604b78
14d42b7a1c
158314145e
hex539105ba

1402013114 has 4 divisors (see below), whose sum is σ = 2103019674. Its totient is φ = 701006556.

The previous prime is 1402013089. The next prime is 1402013131. The reversal of 1402013114 is 4113102041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4113102041 = 31132680711.

It can be written as a sum of positive squares in only one way, i.e., 1034715889 + 367297225 = 32167^2 + 19165^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1402013092 and 1402013101.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 350503277 + ... + 350503280.

Almost surely, 21402013114 is an apocalyptic number.

1402013114 is a deficient number, since it is larger than the sum of its proper divisors (701006560).

1402013114 is an equidigital number, since it uses as much as digits as its factorization.

1402013114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 701006559.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1402013114 is about 37443.4655714452. The cubic root of 1402013114 is about 1119.2248872711.

Adding to 1402013114 its reverse (4113102041), we get a palindrome (5515115155).

The spelling of 1402013114 in words is "one billion, four hundred two million, thirteen thousand, one hundred fourteen".

Divisors: 1 2 701006557 1402013114