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14020224310481 is a prime number
BaseRepresentation
bin1100110000000101011001…
…1111010101110011010001
31211122022122112112101010212
43030001112133111303101
53314201404410413411
645452445132133505
72644633141222634
oct314012637256321
954568575471125
1014020224310481
114515a42131474
1216a5268907295
137a9141c4827c
14366822463c1b
15194a716c668b
hexcc0567d5cd1

14020224310481 has 2 divisors, whose sum is σ = 14020224310482. Its totient is φ = 14020224310480.

The previous prime is 14020224310361. The next prime is 14020224310531. The reversal of 14020224310481 is 18401342202041.

14020224310481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12840863062225 + 1179361248256 = 3583415^2 + 1085984^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14020224310481 is a prime.

It is a super-2 number, since 2×140202243104812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14020224319481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010112155240 + 7010112155241.

It is an arithmetic number, because the mean of its divisors is an integer number (7010112155241).

Almost surely, 214020224310481 is an apocalyptic number.

It is an amenable number.

14020224310481 is a deficient number, since it is larger than the sum of its proper divisors (1).

14020224310481 is an equidigital number, since it uses as much as digits as its factorization.

14020224310481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12288, while the sum is 32.

The spelling of 14020224310481 in words is "fourteen trillion, twenty billion, two hundred twenty-four million, three hundred ten thousand, four hundred eighty-one".