Base | Representation |
---|---|
bin | 10100011001101111101… |
… | …111101111011010010101 |
3 | 11222000220011120000121222 |
4 | 110121233233233122111 |
5 | 140432331213440222 |
6 | 2552030253020125 |
7 | 203202466266002 |
oct | 24315757573225 |
9 | 4860804500558 |
10 | 1402034124437 |
11 | 4a0665792071 |
12 | 1a7882484645 |
13 | a229916b5bb |
14 | 4bc048288a9 |
15 | 2670ba13542 |
hex | 1466fbef695 |
1402034124437 has 2 divisors, whose sum is σ = 1402034124438. Its totient is φ = 1402034124436.
The previous prime is 1402034124427. The next prime is 1402034124443. The reversal of 1402034124437 is 7344214302041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1178410118116 + 223624006321 = 1085546^2 + 472889^2 .
It is a cyclic number.
It is not a de Polignac number, because 1402034124437 - 28 = 1402034124181 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1402034124397 and 1402034124406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1402034124427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701017062218 + 701017062219.
It is an arithmetic number, because the mean of its divisors is an integer number (701017062219).
Almost surely, 21402034124437 is an apocalyptic number.
It is an amenable number.
1402034124437 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402034124437 is an equidigital number, since it uses as much as digits as its factorization.
1402034124437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 1402034124437 its reverse (7344214302041), we get a palindrome (8746248426478).
The spelling of 1402034124437 in words is "one trillion, four hundred two billion, thirty-four million, one hundred twenty-four thousand, four hundred thirty-seven".
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