Search a number
-
+
14021220013 = 53264551321
BaseRepresentation
bin11010000111011101…
…01101011010101101
31100012011101202221221
431003232231122231
5212203413020023
610235151223341
71004313255313
oct150356553255
940164352857
1014021220013
115a45682139
122873817b51
131425b2b6b8
1497023c0b3
15570e2585d
hex343bad6ad

14021220013 has 4 divisors (see below), whose sum is σ = 14285771388. Its totient is φ = 13756668640.

The previous prime is 14021219959. The next prime is 14021220019. The reversal of 14021220013 is 31002212041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12086363844 + 1934856169 = 109938^2 + 43987^2 .

It is a cyclic number.

It is not a de Polignac number, because 14021220013 - 213 = 14021211821 is a prime.

It is a super-2 number, since 2×140212200132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14021220019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132275608 + ... + 132275713.

It is an arithmetic number, because the mean of its divisors is an integer number (3571442847).

Almost surely, 214021220013 is an apocalyptic number.

It is an amenable number.

14021220013 is a deficient number, since it is larger than the sum of its proper divisors (264551375).

14021220013 is an equidigital number, since it uses as much as digits as its factorization.

14021220013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 264551374.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 14021220013 its reverse (31002212041), we get a palindrome (45023432054).

The spelling of 14021220013 in words is "fourteen billion, twenty-one million, two hundred twenty thousand, thirteen".

Divisors: 1 53 264551321 14021220013