Base | Representation |
---|---|
bin | 10100011001110100111… |
… | …111110100001100010001 |
3 | 11222001010022022222001121 |
4 | 110121310333310030101 |
5 | 140433021242140101 |
6 | 2552043121202241 |
7 | 203204616156133 |
oct | 24316477641421 |
9 | 4861108288047 |
10 | 1402122224401 |
11 | 4a0700495958 |
12 | 1a78a7a90381 |
13 | a22b14a6762 |
14 | 4bc123dd053 |
15 | 267146170a1 |
hex | 14674ff4311 |
1402122224401 has 2 divisors, whose sum is σ = 1402122224402. Its totient is φ = 1402122224400.
The previous prime is 1402122224387. The next prime is 1402122224417. The reversal of 1402122224401 is 1044222212041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1205057258001 + 197064966400 = 1097751^2 + 443920^2 .
It is a cyclic number.
It is not a de Polignac number, because 1402122224401 - 29 = 1402122223889 is a prime.
It is not a weakly prime, because it can be changed into another prime (1402122224101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701061112200 + 701061112201.
It is an arithmetic number, because the mean of its divisors is an integer number (701061112201).
Almost surely, 21402122224401 is an apocalyptic number.
It is an amenable number.
1402122224401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402122224401 is an equidigital number, since it uses as much as digits as its factorization.
1402122224401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2048, while the sum is 25.
Adding to 1402122224401 its reverse (1044222212041), we get a palindrome (2446344436442).
The spelling of 1402122224401 in words is "one trillion, four hundred two billion, one hundred twenty-two million, two hundred twenty-four thousand, four hundred one".
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