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140213100013020 = 2233510738943314407
BaseRepresentation
bin11111111000010111101000…
…000001001110010111011100
3200101110020112000111211122000
4133320113220001032113130
5121334222412100404040
61214113001531522300
741351030220355626
oct3770275001162734
9611406460454560
10140213100013020
1140749050678091
12138862a35b9390
136031066a4ac68
14268a4c912dc16
1511323e7a6b130
hex7f85e804e5dc

140213100013020 has 384 divisors, whose sum is σ = 442477379635200. Its totient is φ = 36857615929344.

The previous prime is 140213100013001. The next prime is 140213100013141. The reversal of 140213100013020 is 20310001312041.

140213100013020 is a `hidden beast` number, since 1 + 402 + 13 + 100 + 0 + 130 + 20 = 666.

It is a super-2 number, since 2×1402131000130202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 140213100012984 and 140213100013002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 9732282657 + ... + 9732297063.

It is an arithmetic number, because the mean of its divisors is an integer number (1152284842800).

Almost surely, 2140213100013020 is an apocalyptic number.

140213100013020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 140213100013020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (221238689817600).

140213100013020 is an abundant number, since it is smaller than the sum of its proper divisors (302264279622180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140213100013020 is a wasteful number, since it uses less digits than its factorization.

140213100013020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15354 (or 15346 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 140213100013020 its reverse (20310001312041), we get a palindrome (160523101325061).

The spelling of 140213100013020 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred million, thirteen thousand, twenty".