140213101433140 has 12 divisors (see below), whose sum is σ = 294447513009636. Its totient is φ = 56085240573248.

The previous prime is 140213101433129. The next prime is 140213101433159. The reversal of 140213101433140 is 41334101312041.

It can be written as a sum of positive squares in 2 ways, for example, as 107619004585764 + 32594096847376 = 10373958^2 + 5709124^2 .

It is a junction number, because it is equal to n+sod(n) for n = 140213101433099 and 140213101433108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3505327535809 + ... + 3505327535848.

It is an arithmetic number, because the mean of its divisors is an integer number (24537292750803).

Almost surely, 2^{140213101433140} is an apocalyptic number.

140213101433140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

140213101433140 is an abundant number, since it is smaller than the sum of its proper divisors (154234411576496).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140213101433140 is a wasteful number, since it uses less digits than its factorization.

140213101433140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7010655071666 (or 7010655071664 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 140213101433140 its reverse (41334101312041), we get a palindrome (181547202745181).

The spelling of 140213101433140 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred one million, four hundred thirty-three thousand, one hundred forty".