Base | Representation |
---|---|
bin | 11111111000010111101000… |
… | …101011111001101001010110 |
3 | 200101110020112210120012202021 |
4 | 133320113220223321221112 |
5 | 121334222422431402332 |
6 | 1214113003011403354 |
7 | 41351030414432005 |
oct | 3770275053715126 |
9 | 611406483505667 |
10 | 140213111200342 |
11 | 40749056a19304 |
12 | 138862a72b355a |
13 | 603106916708b |
14 | 268a4ca802c3c |
15 | 11323e8a2ac97 |
hex | 7f85e8af9a56 |
140213111200342 has 4 divisors (see below), whose sum is σ = 210319666800516. Its totient is φ = 70106555600170.
The previous prime is 140213111200321. The next prime is 140213111200363. The reversal of 140213111200342 is 243002111312041.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (140213111200321) and next prime (140213111200363).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35053277800084 + ... + 35053277800087.
It is an arithmetic number, because the mean of its divisors is an integer number (52579916700129).
Almost surely, 2140213111200342 is an apocalyptic number.
140213111200342 is a deficient number, since it is larger than the sum of its proper divisors (70106555600174).
140213111200342 is an equidigital number, since it uses as much as digits as its factorization.
140213111200342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70106555600173.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 140213111200342 its reverse (243002111312041), we get a palindrome (383215222512383).
The spelling of 140213111200342 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred eleven million, two hundred thousand, three hundred forty-two".
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