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14021311133057 is a prime number
BaseRepresentation
bin1100110000001001011101…
…0001001111010110000001
31211122102110021120200102212
43030002113101033112001
53314211121122224212
645453145034351505
72645002106113604
oct314022721172601
954572407520385
1014021311133057
11451644a666348
1216a551088b595
137a9286164057
143668c693233b
15194ad6d07e22
hexcc09744f581

14021311133057 has 2 divisors, whose sum is σ = 14021311133058. Its totient is φ = 14021311133056.

The previous prime is 14021311133021. The next prime is 14021311133069. The reversal of 14021311133057 is 75033111312041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13981624118401 + 39687014656 = 3739201^2 + 199216^2 .

It is a cyclic number.

It is not a de Polignac number, because 14021311133057 - 210 = 14021311132033 is a prime.

It is not a weakly prime, because it can be changed into another prime (14021311133077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010655566528 + 7010655566529.

It is an arithmetic number, because the mean of its divisors is an integer number (7010655566529).

Almost surely, 214021311133057 is an apocalyptic number.

It is an amenable number.

14021311133057 is a deficient number, since it is larger than the sum of its proper divisors (1).

14021311133057 is an equidigital number, since it uses as much as digits as its factorization.

14021311133057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7560, while the sum is 32.

Adding to 14021311133057 its reverse (75033111312041), we get a palindrome (89054422445098).

The spelling of 14021311133057 in words is "fourteen trillion, twenty-one billion, three hundred eleven million, one hundred thirty-three thousand, fifty-seven".