140213112019 has 2 divisors, whose sum is σ = 140213112020. Its totient is φ = 140213112018.

The previous prime is 140213111963. The next prime is 140213112031. The reversal of 140213112019 is 910211312041.

It is a strong prime.

It is an emirp because it is prime and its reverse (910211312041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140213112019 - 2²⁵ = 140179557587 is a prime.

It is a super-2 number, since 2×140213112019² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140213111984 and 140213112002.

It is not a weakly prime, because it can be changed into another prime (140213112059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106556009 + 70106556010.

It is an arithmetic number, because the mean of its divisors is an integer number (70106556010).

Almost surely, 2^140213112019 is an apocalyptic number.

140213112019 is a deficient number, since it is larger than the sum of its proper divisors (1).

140213112019 is an equidigital number, since it uses as much as digits as its factorization.

140213112019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 140213112019 in words is "one hundred forty billion, two hundred thirteen million, one hundred twelve thousand, nineteen".