140213112024330 has 48 divisors (see below), whose sum is σ = 364657394467080. Its totient is φ = 37379568006144.

The previous prime is 140213112024329. The next prime is 140213112024331. The reversal of 140213112024330 is 33420211312041.

140213112024330 is a `hidden beast` number, since 1 + 4 + 0 + 2 + 13 + 11 + 202 + 433 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (140213112024329) and next prime (140213112024331).

It can be written as a sum of positive squares in 4 ways, for example, as 44007793342569 + 96205318681761 = 6633837^2 + 9808431^2 .

It is a junction number, because it is equal to n+sod(n) for n = 140213112024294 and 140213112024303.

It is not an unprimeable number, because it can be changed into a prime (140213112024331) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 220413967 + ... + 221049186.

Almost surely, 2^{140213112024330} is an apocalyptic number.

140213112024330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

140213112024330 is an abundant number, since it is smaller than the sum of its proper divisors (224444282442750).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140213112024330 is a wasteful number, since it uses less digits than its factorization.

140213112024330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 441466695 (or 441466692 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 140213112024330 its reverse (33420211312041), we get a palindrome (173633323336371).

The spelling of 140213112024330 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred twelve million, twenty-four thousand, three hundred thirty".