Base | Representation |
---|---|
bin | 11010000111011110… |
… | …00110101010110001 |
3 | 1100012011121000211121 |
4 | 31003233012222301 |
5 | 212203424322231 |
6 | 10235153342241 |
7 | 1004314165666 |
oct | 150357065261 |
9 | 40164530747 |
10 | 14021323441 |
11 | 5a45742914 |
12 | 2873867981 |
13 | 1425b667b8 |
14 | 970267a6d |
15 | 570e46311 |
hex | 343bc6ab1 |
14021323441 has 2 divisors, whose sum is σ = 14021323442. Its totient is φ = 14021323440.
The previous prime is 14021323417. The next prime is 14021323483. The reversal of 14021323441 is 14432312041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9011515041 + 5009808400 = 94929^2 + 70780^2 .
It is a cyclic number.
It is not a de Polignac number, because 14021323441 - 221 = 14019226289 is a prime.
It is a super-2 number, since 2×140213234412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14021323741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010661720 + 7010661721.
It is an arithmetic number, because the mean of its divisors is an integer number (7010661721).
Almost surely, 214021323441 is an apocalyptic number.
It is an amenable number.
14021323441 is a deficient number, since it is larger than the sum of its proper divisors (1).
14021323441 is an equidigital number, since it uses as much as digits as its factorization.
14021323441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14021323441 its reverse (14432312041), we get a palindrome (28453635482).
The spelling of 14021323441 in words is "fourteen billion, twenty-one million, three hundred twenty-three thousand, four hundred forty-one".
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