140213324013001 has 2 divisors, whose sum is σ = 140213324013002. Its totient is φ = 140213324013000.

The previous prime is 140213324012987. The next prime is 140213324013029. The reversal of 140213324013001 is 100310423312041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106279192272400 + 33934131740601 = 10309180^2 + 5825301^2 .

It is an emirp because it is prime and its reverse (100310423312041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140213324013001 - 2¹⁷ = 140213323881929 is a prime.

It is not a weakly prime, because it can be changed into another prime (140213324013601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106662006500 + 70106662006501.

It is an arithmetic number, because the mean of its divisors is an integer number (70106662006501).

Almost surely, 2^{140213324013001} is an apocalyptic number.

It is an amenable number.

140213324013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

140213324013001 is an equidigital number, since it uses as much as digits as its factorization.

140213324013001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 140213324013001 its reverse (100310423312041), we get a palindrome (240523747325042).

The spelling of 140213324013001 in words is "one hundred forty trillion, two hundred thirteen billion, three hundred twenty-four million, thirteen thousand, one".