Base | Representation |
---|---|
bin | 11111111000010111110101… |
… | …010111101111000101001111 |
3 | 200101110021002122000110200201 |
4 | 133320113311113233011033 |
5 | 121334223341422033444 |
6 | 1214113040053034331 |
7 | 41351035610362441 |
oct | 3770276527570517 |
9 | 611407078013621 |
10 | 140213324017999 |
11 | 40749156066371 |
12 | 138863466259a7 |
13 | 60310a128b59b |
14 | 268a50aba0491 |
15 | 113240c567dd4 |
hex | 7f85f55ef14f |
140213324017999 has 2 divisors, whose sum is σ = 140213324018000. Its totient is φ = 140213324017998.
The previous prime is 140213324017939. The next prime is 140213324018017. The reversal of 140213324017999 is 999710423312041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140213324017999 - 211 = 140213324015951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140213324017939) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106662008999 + 70106662009000.
It is an arithmetic number, because the mean of its divisors is an integer number (70106662009000).
Almost surely, 2140213324017999 is an apocalyptic number.
140213324017999 is a deficient number, since it is larger than the sum of its proper divisors (1).
140213324017999 is an equidigital number, since it uses as much as digits as its factorization.
140213324017999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2939328, while the sum is 55.
The spelling of 140213324017999 in words is "one hundred forty trillion, two hundred thirteen billion, three hundred twenty-four million, seventeen thousand, nine hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •