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14021333210047 is a prime number
BaseRepresentation
bin1100110000001001100010…
…0101011101001110111111
31211122102111211010022101011
43030002120211131032333
53314211142300210142
645453151143500051
72645002464553162
oct314023045351677
954572454108334
1014021333210047
114516461075099
1216a5518157627
137a928a8c3967
143668c983bad9
15194ad8c19417
hexcc09895d3bf

14021333210047 has 2 divisors, whose sum is σ = 14021333210048. Its totient is φ = 14021333210046.

The previous prime is 14021333210033. The next prime is 14021333210077. The reversal of 14021333210047 is 74001233312041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14021333210047 - 239 = 13471577396159 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14021333210077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010666605023 + 7010666605024.

It is an arithmetic number, because the mean of its divisors is an integer number (7010666605024).

Almost surely, 214021333210047 is an apocalyptic number.

14021333210047 is a deficient number, since it is larger than the sum of its proper divisors (1).

14021333210047 is an equidigital number, since it uses as much as digits as its factorization.

14021333210047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 14021333210047 its reverse (74001233312041), we get a palindrome (88022566522088).

The spelling of 14021333210047 in words is "fourteen trillion, twenty-one billion, three hundred thirty-three million, two hundred ten thousand, forty-seven".