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1402140240313 is a prime number
BaseRepresentation
bin10100011001110110000…
…100100010100110111001
311222001011120020021020121
4110121312010202212321
5140433040400142223
62552045003253241
7203205225252511
oct24316604424671
94861146207217
101402140240313
114a070a68053a
121a78b1b1a221
13a22b5143a67
144bc1496c841
1526715ec515d
hex146761229b9

1402140240313 has 2 divisors, whose sum is σ = 1402140240314. Its totient is φ = 1402140240312.

The previous prime is 1402140240287. The next prime is 1402140240331. The reversal of 1402140240313 is 3130420412041.

Together with next prime (1402140240331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1118490262569 + 283649977744 = 1057587^2 + 532588^2 .

It is a cyclic number.

It is not a de Polignac number, because 1402140240313 - 217 = 1402140109241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1402144240313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701070120156 + 701070120157.

It is an arithmetic number, because the mean of its divisors is an integer number (701070120157).

Almost surely, 21402140240313 is an apocalyptic number.

It is an amenable number.

1402140240313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402140240313 is an equidigital number, since it uses as much as digits as its factorization.

1402140240313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1402140240313 its reverse (3130420412041), we get a palindrome (4532560652354).

The spelling of 1402140240313 in words is "one trillion, four hundred two billion, one hundred forty million, two hundred forty thousand, three hundred thirteen".