140214120402017 has 2 divisors, whose sum is σ = 140214120402018. Its totient is φ = 140214120402016.

The previous prime is 140214120401981. The next prime is 140214120402019. The reversal of 140214120402017 is 710204021412041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134217577323361 + 5996543078656 = 11585231^2 + 2448784^2 .

It is a cyclic number.

It is not a de Polignac number, because 140214120402017 - 2³⁴ = 140196940532833 is a prime.

It is a super-2 number, since 2×140214120402017² (a number of 29 digits) contains 22 as substring.

Together with 140214120402019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (140214120402019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70107060201008 + 70107060201009.

It is an arithmetic number, because the mean of its divisors is an integer number (70107060201009).

Almost surely, 2^{140214120402017} is an apocalyptic number.

It is an amenable number.

140214120402017 is a deficient number, since it is larger than the sum of its proper divisors (1).

140214120402017 is an equidigital number, since it uses as much as digits as its factorization.

140214120402017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3584, while the sum is 29.

Adding to 140214120402017 its reverse (710204021412041), we get a palindrome (850418141814058).

The spelling of 140214120402017 in words is "one hundred forty trillion, two hundred fourteen billion, one hundred twenty million, four hundred two thousand, seventeen".