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140220302343313 is a prime number
BaseRepresentation
bin11111111000011110010101…
…010011111011110010010001
3200101110221002221222010101211
4133320132111103323302101
5121334332134344441223
61214120152334500121
741351403544226263
oct3770362523736221
9611427087863354
10140220302343313
1140751107156475
1213887773664641
136031943c45a6a
14268a9ad8b7b33
1511326b9eeed0d
hex7f87954fbc91

140220302343313 has 2 divisors, whose sum is σ = 140220302343314. Its totient is φ = 140220302343312.

The previous prime is 140220302343287. The next prime is 140220302343349. The reversal of 140220302343313 is 313343203022041.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133738654798849 + 6481647544464 = 11564543^2 + 2545908^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140220302343313 is a prime.

It is not a weakly prime, because it can be changed into another prime (140220302343613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70110151171656 + 70110151171657.

It is an arithmetic number, because the mean of its divisors is an integer number (70110151171657).

Almost surely, 2140220302343313 is an apocalyptic number.

It is an amenable number.

140220302343313 is a deficient number, since it is larger than the sum of its proper divisors (1).

140220302343313 is an equidigital number, since it uses as much as digits as its factorization.

140220302343313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 140220302343313 its reverse (313343203022041), we get a palindrome (453563505365354).

The spelling of 140220302343313 in words is "one hundred forty trillion, two hundred twenty billion, three hundred two million, three hundred forty-three thousand, three hundred thirteen".