Base | Representation |
---|---|
bin | 11111111000100001111010… |
… | …000011100001100101010111 |
3 | 200101111022000102020111211011 |
4 | 133320201322003201211113 |
5 | 121334413014321233101 |
6 | 1214122025225353051 |
7 | 41351600624044201 |
oct | 3770417203414527 |
9 | 611438012214734 |
10 | 140224140024151 |
11 | 407527a6453927 |
12 | 13888464938787 |
13 | 6032106044221 |
14 | 268ac55457771 |
15 | 1132841db0751 |
hex | 7f887a0e1957 |
140224140024151 has 2 divisors, whose sum is σ = 140224140024152. Its totient is φ = 140224140024150.
The previous prime is 140224140024013. The next prime is 140224140024169. The reversal of 140224140024151 is 151420041422041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140224140024151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140224140094151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70112070012075 + 70112070012076.
It is an arithmetic number, because the mean of its divisors is an integer number (70112070012076).
Almost surely, 2140224140024151 is an apocalyptic number.
140224140024151 is a deficient number, since it is larger than the sum of its proper divisors (1).
140224140024151 is an equidigital number, since it uses as much as digits as its factorization.
140224140024151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10240, while the sum is 31.
Adding to 140224140024151 its reverse (151420041422041), we get a palindrome (291644181446192).
The spelling of 140224140024151 in words is "one hundred forty trillion, two hundred twenty-four billion, one hundred forty million, twenty-four thousand, one hundred fifty-one".
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