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14022433131 = 37667734911
BaseRepresentation
bin11010000111100110…
…10101100101101011
31100012020200102001020
431003303111211223
5212204220330011
610235233223523
71004326500150
oct150363254553
940166612036
1014022433131
115a46330613
122874101ba3
131426164915
14970476227
155710b5006
hex343cd596b

14022433131 has 8 divisors (see below), whose sum is σ = 21367517184. Its totient is φ = 8012818920.

The previous prime is 14022433121. The next prime is 14022433147. The reversal of 14022433131 is 13133422041.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14022433131 - 222 = 14018238827 is a prime.

It is a super-2 number, since 2×140224331312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14022433121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 333867435 + ... + 333867476.

It is an arithmetic number, because the mean of its divisors is an integer number (2670939648).

Almost surely, 214022433131 is an apocalyptic number.

14022433131 is a deficient number, since it is larger than the sum of its proper divisors (7345084053).

14022433131 is an equidigital number, since it uses as much as digits as its factorization.

14022433131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 667734921.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 14022433131 its reverse (13133422041), we get a palindrome (27155855172).

The spelling of 14022433131 in words is "fourteen billion, twenty-two million, four hundred thirty-three thousand, one hundred thirty-one".

Divisors: 1 3 7 21 667734911 2003204733 4674144377 14022433131