Base | Representation |
---|---|
bin | 11111111000101000011010… |
… | …111011110110101001001111 |
3 | 200101111222001211212000010021 |
4 | 133320220122323312221033 |
5 | 121340021330313043320 |
6 | 1214125143233123011 |
7 | 41352236141601640 |
oct | 3770503273665117 |
9 | 611458054760107 |
10 | 140231134112335 |
11 | 4075576542a8a2 |
12 | 138898970b9467 |
13 | 603297c05a346 |
14 | 268b31a2b56c7 |
15 | 1132b00e0cdaa |
hex | 7f8a1aef6a4f |
140231134112335 has 32 divisors (see below), whose sum is σ = 194978161918080. Its totient is φ = 94828263763968.
The previous prime is 140231134112327. The next prime is 140231134112389. The reversal of 140231134112335 is 533211431132041.
It is not a de Polignac number, because 140231134112335 - 23 = 140231134112327 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 140231134112335.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14919879 + ... + 22429111.
It is an arithmetic number, because the mean of its divisors is an integer number (6093067559940).
Almost surely, 2140231134112335 is an apocalyptic number.
140231134112335 is a deficient number, since it is larger than the sum of its proper divisors (54747027805745).
140231134112335 is an equidigital number, since it uses as much as digits as its factorization.
140231134112335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7516627.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 140231134112335 its reverse (533211431132041), we get a palindrome (673442565244376).
The spelling of 140231134112335 in words is "one hundred forty trillion, two hundred thirty-one billion, one hundred thirty-four million, one hundred twelve thousand, three hundred thirty-five".
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