14023113433141 has 2 divisors, whose sum is σ = 14023113433142. Its totient is φ = 14023113433140.

The previous prime is 14023113433099. The next prime is 14023113433163. The reversal of 14023113433141 is 14133431132041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13928943622500 + 94169810641 = 3732150^2 + 306871^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14023113433141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14023113433741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011556716570 + 7011556716571.

It is an arithmetic number, because the mean of its divisors is an integer number (7011556716571).

Almost surely, 2^{14023113433141} is an apocalyptic number.

It is an amenable number.

14023113433141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14023113433141 is an equidigital number, since it uses as much as digits as its factorization.

14023113433141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 14023113433141 its reverse (14133431132041), we get a palindrome (28156544565182).

The spelling of 14023113433141 in words is "fourteen trillion, twenty-three billion, one hundred thirteen million, four hundred thirty-three thousand, one hundred forty-one".