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140233300011313 is a prime number
BaseRepresentation
bin11111111000101010011100…
…000010000110100100110001
3200101112011122210101001221221
4133320222130002012210301
5121340040244300330223
61214130142203545041
741352343621462135
oct3770523402064461
9611464583331857
10140233300011313
1140756676a88853
121388a1a052b181
136032c359ac182
14268b483bd73c5
151132bcb140b5d
hex7f8a9c086931

140233300011313 has 2 divisors, whose sum is σ = 140233300011314. Its totient is φ = 140233300011312.

The previous prime is 140233300011209. The next prime is 140233300011319. The reversal of 140233300011313 is 313110003332041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101267028175104 + 38966271836209 = 10063152^2 + 6242297^2 .

It is a cyclic number.

It is not a de Polignac number, because 140233300011313 - 233 = 140224710076721 is a prime.

It is not a weakly prime, because it can be changed into another prime (140233300011319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70116650005656 + 70116650005657.

It is an arithmetic number, because the mean of its divisors is an integer number (70116650005657).

Almost surely, 2140233300011313 is an apocalyptic number.

It is an amenable number.

140233300011313 is a deficient number, since it is larger than the sum of its proper divisors (1).

140233300011313 is an equidigital number, since it uses as much as digits as its factorization.

140233300011313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 140233300011313 its reverse (313110003332041), we get a palindrome (453343303343354).

The spelling of 140233300011313 in words is "one hundred forty trillion, two hundred thirty-three billion, three hundred million, eleven thousand, three hundred thirteen".