Base | Representation |
---|---|
bin | 11111111000101010011100… |
… | …000010000110100100110001 |
3 | 200101112011122210101001221221 |
4 | 133320222130002012210301 |
5 | 121340040244300330223 |
6 | 1214130142203545041 |
7 | 41352343621462135 |
oct | 3770523402064461 |
9 | 611464583331857 |
10 | 140233300011313 |
11 | 40756676a88853 |
12 | 1388a1a052b181 |
13 | 6032c359ac182 |
14 | 268b483bd73c5 |
15 | 1132bcb140b5d |
hex | 7f8a9c086931 |
140233300011313 has 2 divisors, whose sum is σ = 140233300011314. Its totient is φ = 140233300011312.
The previous prime is 140233300011209. The next prime is 140233300011319. The reversal of 140233300011313 is 313110003332041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101267028175104 + 38966271836209 = 10063152^2 + 6242297^2 .
It is a cyclic number.
It is not a de Polignac number, because 140233300011313 - 233 = 140224710076721 is a prime.
It is not a weakly prime, because it can be changed into another prime (140233300011319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70116650005656 + 70116650005657.
It is an arithmetic number, because the mean of its divisors is an integer number (70116650005657).
Almost surely, 2140233300011313 is an apocalyptic number.
It is an amenable number.
140233300011313 is a deficient number, since it is larger than the sum of its proper divisors (1).
140233300011313 is an equidigital number, since it uses as much as digits as its factorization.
140233300011313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 140233300011313 its reverse (313110003332041), we get a palindrome (453343303343354).
The spelling of 140233300011313 in words is "one hundred forty trillion, two hundred thirty-three billion, three hundred million, eleven thousand, three hundred thirteen".
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