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140241212533 is a prime number
BaseRepresentation
bin1000001010011100000…
…1110001010001110101
3111101222122120202010201
42002213001301101311
54244203222300113
6144231555520501
713063210431562
oct2024701612165
9441878522121
10140241212533
1154526565744
122321a5b9131
13102bc8489c6
146b0569b869
1539abebbcdd
hex20a7071475

140241212533 has 2 divisors, whose sum is σ = 140241212534. Its totient is φ = 140241212532.

The previous prime is 140241212473. The next prime is 140241212597. The reversal of 140241212533 is 335212142041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107294243364 + 32946969169 = 327558^2 + 181513^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140241212533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140241212333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70120606266 + 70120606267.

It is an arithmetic number, because the mean of its divisors is an integer number (70120606267).

Almost surely, 2140241212533 is an apocalyptic number.

It is an amenable number.

140241212533 is a deficient number, since it is larger than the sum of its proper divisors (1).

140241212533 is an equidigital number, since it uses as much as digits as its factorization.

140241212533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 140241212533 its reverse (335212142041), we get a palindrome (475453354574).

The spelling of 140241212533 in words is "one hundred forty billion, two hundred forty-one million, two hundred twelve thousand, five hundred thirty-three".