Base | Representation |
---|---|
bin | 10100011010000110010… |
… | …010000010000011000111 |
3 | 11222001212111222212211201 |
4 | 110122012102002003013 |
5 | 140434120011244143 |
6 | 2552132000443331 |
7 | 203215040056225 |
oct | 24320622020307 |
9 | 4861774885751 |
10 | 1402412212423 |
11 | 4a083a151182 |
12 | 1a7969019547 |
13 | a23295aa3c1 |
14 | 4bc3cb27b15 |
15 | 2672ece964d |
hex | 146864820c7 |
1402412212423 has 2 divisors, whose sum is σ = 1402412212424. Its totient is φ = 1402412212422.
The previous prime is 1402412212367. The next prime is 1402412212549. The reversal of 1402412212423 is 3242122142041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1402412212423 - 29 = 1402412211911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1402412212391 and 1402412212400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1402412215423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701206106211 + 701206106212.
It is an arithmetic number, because the mean of its divisors is an integer number (701206106212).
Almost surely, 21402412212423 is an apocalyptic number.
1402412212423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402412212423 is an equidigital number, since it uses as much as digits as its factorization.
1402412212423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 1402412212423 its reverse (3242122142041), we get a palindrome (4644534354464).
The spelling of 1402412212423 in words is "one trillion, four hundred two billion, four hundred twelve million, two hundred twelve thousand, four hundred twenty-three".
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