Base | Representation |
---|---|
bin | 11111111000110011110000… |
… | …001001101010001101001111 |
3 | 200101120010110210101202111111 |
4 | 133320303300021222031033 |
5 | 121340221240102304012 |
6 | 1214134514432232451 |
7 | 41353146512340436 |
oct | 3770636011521517 |
9 | 611503423352444 |
10 | 140243301213007 |
11 | 4075a9394436a3 |
12 | 1389011199b727 |
13 | 6033b6a9ca5b5 |
14 | 268bb5219011d |
15 | 11330b4189ba7 |
hex | 7f8cf026a34f |
140243301213007 has 2 divisors, whose sum is σ = 140243301213008. Its totient is φ = 140243301213006.
The previous prime is 140243301212999. The next prime is 140243301213017. The reversal of 140243301213007 is 700312103342041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140243301213007 - 23 = 140243301212999 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 140243301213007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140243301213017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70121650606503 + 70121650606504.
It is an arithmetic number, because the mean of its divisors is an integer number (70121650606504).
Almost surely, 2140243301213007 is an apocalyptic number.
140243301213007 is a deficient number, since it is larger than the sum of its proper divisors (1).
140243301213007 is an equidigital number, since it uses as much as digits as its factorization.
140243301213007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 140243301213007 its reverse (700312103342041), we get a palindrome (840555404555048).
The spelling of 140243301213007 in words is "one hundred forty trillion, two hundred forty-three billion, three hundred one million, two hundred thirteen thousand, seven".
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