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140244245131 is a prime number
BaseRepresentation
bin1000001010011100110…
…1010101101010001011
3111101222212021211002011
42002213031111222023
54244210011321011
6144232144520351
713063245262144
oct2024715255213
9441885254064
10140244245131
1154528247121
122321b6200b7
13102c036b143
146b05c4aacb
1539ac3ba621
hex20a7355a8b

140244245131 has 2 divisors, whose sum is σ = 140244245132. Its totient is φ = 140244245130.

The previous prime is 140244245093. The next prime is 140244245173. The reversal of 140244245131 is 131542442041.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (131542442041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140244245131 - 219 = 140243720843 is a prime.

It is a super-2 number, since 2×1402442451312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140244245093 and 140244245102.

It is not a weakly prime, because it can be changed into another prime (140244245731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70122122565 + 70122122566.

It is an arithmetic number, because the mean of its divisors is an integer number (70122122566).

Almost surely, 2140244245131 is an apocalyptic number.

140244245131 is a deficient number, since it is larger than the sum of its proper divisors (1).

140244245131 is an equidigital number, since it uses as much as digits as its factorization.

140244245131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 140244245131 its reverse (131542442041), we get a palindrome (271786687172).

The spelling of 140244245131 in words is "one hundred forty billion, two hundred forty-four million, two hundred forty-five thousand, one hundred thirty-one".