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140244332113441 is a prime number
BaseRepresentation
bin11111111000110100101101…
…100110001110111000100001
3200101120020010122012221001001
4133320310231212032320201
5121340230343010112231
61214135205020112001
741353214201010163
oct3770645546167041
9611506118187031
10140244332113441
1140760318352426
121389035b095601
136033ca346655a
14268bc0d062933
151133124921b61
hex7f8d2d98ee21

140244332113441 has 2 divisors, whose sum is σ = 140244332113442. Its totient is φ = 140244332113440.

The previous prime is 140244332113433. The next prime is 140244332113489. The reversal of 140244332113441 is 144311233442041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70928466985216 + 69315865128225 = 8421904^2 + 8325615^2 .

It is a cyclic number.

It is not a de Polignac number, because 140244332113441 - 23 = 140244332113433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140244332113441.

It is not a weakly prime, because it can be changed into another prime (140244332113541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70122166056720 + 70122166056721.

It is an arithmetic number, because the mean of its divisors is an integer number (70122166056721).

Almost surely, 2140244332113441 is an apocalyptic number.

It is an amenable number.

140244332113441 is a deficient number, since it is larger than the sum of its proper divisors (1).

140244332113441 is an equidigital number, since it uses as much as digits as its factorization.

140244332113441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 37.

Adding to 140244332113441 its reverse (144311233442041), we get a palindrome (284555565555482).

The spelling of 140244332113441 in words is "one hundred forty trillion, two hundred forty-four billion, three hundred thirty-two million, one hundred thirteen thousand, four hundred forty-one".