140244332113440 has 96 divisors (see below), whose sum is σ = 490855162412160. Its totient is φ = 37398488562432.

The previous prime is 140244332113433. The next prime is 140244332113441. The reversal of 140244332113440 is 44311233442041.

140244332113440 is a `hidden beast` number, since 1 + 4 + 0 + 2 + 4 + 433 + 211 + 3 + 4 + 4 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (96).

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 140244332113395 and 140244332113404.

It is not an unprimeable number, because it can be changed into a prime (140244332113441) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16231978564 + ... + 16231987203.

It is an arithmetic number, because the mean of its divisors is an integer number (5113074608460).

Almost surely, 2^{140244332113440} is an apocalyptic number.

140244332113440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

140244332113440 is an abundant number, since it is smaller than the sum of its proper divisors (350610830298720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140244332113440 is a wasteful number, since it uses less digits than its factorization.

140244332113440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32463965791 (or 32463965777 counting only the distinct ones).

The product of its (nonzero) digits is 110592, while the sum is 36.

Adding to 140244332113440 its reverse (44311233442041), we get a palindrome (184555565555481).

The spelling of 140244332113440 in words is "one hundred forty trillion, two hundred forty-four billion, three hundred thirty-two million, one hundred thirteen thousand, four hundred forty".