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140244334111247 is a prime number
BaseRepresentation
bin11111111000110100101101…
…101101110110101000001111
3200101120020010202222102111212
4133320310231231312220033
5121340230344013024442
61214135205131005035
741353214224000532
oct3770645555665017
9611506122872455
10140244334111247
1140760319497403
121389035b89977b
136033ca39b59a2
14268bc0d422a19
151133124bb8a82
hex7f8d2db76a0f

140244334111247 has 2 divisors, whose sum is σ = 140244334111248. Its totient is φ = 140244334111246.

The previous prime is 140244334111229. The next prime is 140244334111253. The reversal of 140244334111247 is 742111433442041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140244334111247 - 230 = 140243260369423 is a prime.

It is a super-2 number, since 2×1402443341112472 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140244334111447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70122167055623 + 70122167055624.

It is an arithmetic number, because the mean of its divisors is an integer number (70122167055624).

Almost surely, 2140244334111247 is an apocalyptic number.

140244334111247 is a deficient number, since it is larger than the sum of its proper divisors (1).

140244334111247 is an equidigital number, since it uses as much as digits as its factorization.

140244334111247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 258048, while the sum is 41.

Adding to 140244334111247 its reverse (742111433442041), we get a palindrome (882355767553288).

The spelling of 140244334111247 in words is "one hundred forty trillion, two hundred forty-four billion, three hundred thirty-four million, one hundred eleven thousand, two hundred forty-seven".