Base | Representation |
---|---|
bin | 10100011010001100010… |
… | …001001011010101010001 |
3 | 11222002010111222201111021 |
4 | 110122030101023111101 |
5 | 140434321214322401 |
6 | 2552145545315441 |
7 | 203220366560635 |
oct | 24321421132521 |
9 | 4862114881437 |
10 | 1402512651601 |
11 | 4a0890912666 |
12 | 1a7996795b81 |
13 | a2344345a79 |
14 | 4bc4c1d0dc5 |
15 | 26738a392a1 |
hex | 1468c44b551 |
1402512651601 has 2 divisors, whose sum is σ = 1402512651602. Its totient is φ = 1402512651600.
The previous prime is 1402512651581. The next prime is 1402512651607. The reversal of 1402512651601 is 1061562152041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1015410920976 + 387101730625 = 1007676^2 + 622175^2 .
It is a cyclic number.
It is not a de Polignac number, because 1402512651601 - 217 = 1402512520529 is a prime.
It is not a weakly prime, because it can be changed into another prime (1402512651607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701256325800 + 701256325801.
It is an arithmetic number, because the mean of its divisors is an integer number (701256325801).
Almost surely, 21402512651601 is an apocalyptic number.
It is an amenable number.
1402512651601 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402512651601 is an equidigital number, since it uses as much as digits as its factorization.
1402512651601 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 34.
The spelling of 1402512651601 in words is "one trillion, four hundred two billion, five hundred twelve million, six hundred fifty-one thousand, six hundred one".
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