Base | Representation |
---|---|
bin | 1100110000011000000100… |
… | …1001110001001101000111 |
3 | 1211122210120202002222011001 |
4 | 3030012001021301031013 |
5 | 3314242140132340033 |
6 | 45455034245354131 |
7 | 2645201253600652 |
oct | 314060111611507 |
9 | 54583522088131 |
10 | 14025235043143 |
11 | 45180835aa045 |
12 | 16a6226a08947 |
13 | 7a976009403c |
14 | 366b79b1a899 |
15 | 194c6654ce7d |
hex | cc181271347 |
14025235043143 has 2 divisors, whose sum is σ = 14025235043144. Its totient is φ = 14025235043142.
The previous prime is 14025235043077. The next prime is 14025235043153. The reversal of 14025235043143 is 34134053252041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14025235043143 - 29 = 14025235042631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14025235043153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7012617521571 + 7012617521572.
It is an arithmetic number, because the mean of its divisors is an integer number (7012617521572).
Almost surely, 214025235043143 is an apocalyptic number.
14025235043143 is a deficient number, since it is larger than the sum of its proper divisors (1).
14025235043143 is an equidigital number, since it uses as much as digits as its factorization.
14025235043143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 14025235043143 its reverse (34134053252041), we get a palindrome (48159288295184).
The spelling of 14025235043143 in words is "fourteen trillion, twenty-five billion, two hundred thirty-five million, forty-three thousand, one hundred forty-three".
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