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1402544000047 is a prime number
BaseRepresentation
bin10100011010001110001…
…000110000110000101111
311222002012200222101110211
4110122032020300300233
5140434402231000142
62552153025243251
7203221230203551
oct24321610606057
94862180871424
101402544000047
114a08a7584173
121a79a5193527
13a234a9a0748
144bc524314d1
152673b67c917
hex1468e230c2f

1402544000047 has 2 divisors, whose sum is σ = 1402544000048. Its totient is φ = 1402544000046.

The previous prime is 1402543999993. The next prime is 1402544000083. The reversal of 1402544000047 is 7400004452041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1402544000047 - 219 = 1402543475759 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1402543999982 and 1402544000018.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1402544007047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701272000023 + 701272000024.

It is an arithmetic number, because the mean of its divisors is an integer number (701272000024).

Almost surely, 21402544000047 is an apocalyptic number.

1402544000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402544000047 is an equidigital number, since it uses as much as digits as its factorization.

1402544000047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17920, while the sum is 31.

Adding to 1402544000047 its reverse (7400004452041), we get a palindrome (8802548452088).

The spelling of 1402544000047 in words is "one trillion, four hundred two billion, five hundred forty-four million, forty-seven", and thus it is an aban number.