Base | Representation |
---|---|
bin | 10100011010001110101… |
… | …011100110000110010011 |
3 | 11222002020100011022100111 |
4 | 110122032223212012103 |
5 | 140434412100201121 |
6 | 2552153553102151 |
7 | 203221400624605 |
oct | 24321653460623 |
9 | 4862210138314 |
10 | 1402553131411 |
11 | 4a0901750753 |
12 | 1a79a8257957 |
13 | a234c849b13 |
14 | 4bc5372b175 |
15 | 2673c3832e1 |
hex | 1468eae6193 |
1402553131411 has 2 divisors, whose sum is σ = 1402553131412. Its totient is φ = 1402553131410.
The previous prime is 1402553131391. The next prime is 1402553131457. The reversal of 1402553131411 is 1141313552041.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1402553131411 - 213 = 1402553123219 is a prime.
It is not a weakly prime, because it can be changed into another prime (1402553132411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701276565705 + 701276565706.
It is an arithmetic number, because the mean of its divisors is an integer number (701276565706).
Almost surely, 21402553131411 is an apocalyptic number.
1402553131411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402553131411 is an equidigital number, since it uses as much as digits as its factorization.
1402553131411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 1402553131411 its reverse (1141313552041), we get a palindrome (2543866683452).
The spelling of 1402553131411 in words is "one trillion, four hundred two billion, five hundred fifty-three million, one hundred thirty-one thousand, four hundred eleven".
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