Base | Representation |
---|---|
bin | 1000001010100010011… |
… | …1111111111111101111 |
3 | 111102001112000021102011 |
4 | 2002220213333333233 |
5 | 4244232102332003 |
6 | 144234354142051 |
7 | 13063654265644 |
oct | 2025047777757 |
9 | 442045007364 |
10 | 140268011503 |
11 | 5453a6aa154 |
12 | 23227581927 |
13 | 102c526c999 |
14 | 6b09075dcb |
15 | 39ae51246d |
hex | 20a89fffef |
140268011503 has 2 divisors, whose sum is σ = 140268011504. Its totient is φ = 140268011502.
The previous prime is 140268011479. The next prime is 140268011549. The reversal of 140268011503 is 305110862041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140268011503 - 221 = 140265914351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140268011573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70134005751 + 70134005752.
It is an arithmetic number, because the mean of its divisors is an integer number (70134005752).
Almost surely, 2140268011503 is an apocalyptic number.
140268011503 is a deficient number, since it is larger than the sum of its proper divisors (1).
140268011503 is an equidigital number, since it uses as much as digits as its factorization.
140268011503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 140268011503 its reverse (305110862041), we get a palindrome (445378873544).
The spelling of 140268011503 in words is "one hundred forty billion, two hundred sixty-eight million, eleven thousand, five hundred three".
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