Base | Representation |
---|---|
bin | 1100110000101010101110… |
… | …0010001000011011100111 |
3 | 1211200021111121202221222212 |
4 | 3030022223202020123213 |
5 | 3314332413201240403 |
6 | 45501223113314035 |
7 | 2645436311063201 |
oct | 314125342103347 |
9 | 54607447687885 |
10 | 14030241040103 |
11 | 451a212332712 |
12 | 16a71a340591b |
13 | 7aa07a242412 |
14 | 3670d28dd771 |
15 | 194e5ac8b4d8 |
hex | cc2ab8886e7 |
14030241040103 has 2 divisors, whose sum is σ = 14030241040104. Its totient is φ = 14030241040102.
The previous prime is 14030241040073. The next prime is 14030241040121. The reversal of 14030241040103 is 30104014203041.
It is a strong prime.
It is an emirp because it is prime and its reverse (30104014203041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14030241040103 - 226 = 14030173931239 is a prime.
It is a super-2 number, since 2×140302410401032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14030241049103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015120520051 + 7015120520052.
It is an arithmetic number, because the mean of its divisors is an integer number (7015120520052).
Almost surely, 214030241040103 is an apocalyptic number.
14030241040103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14030241040103 is an equidigital number, since it uses as much as digits as its factorization.
14030241040103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14030241040103 its reverse (30104014203041), we get a palindrome (44134255243144).
The spelling of 14030241040103 in words is "fourteen trillion, thirty billion, two hundred forty-one million, forty thousand, one hundred three".
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