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14030245531507 is a prime number
BaseRepresentation
bin1100110000101010101111…
…0011010000111101110011
31211200021111221020011001011
43030022223303100331303
53314332420324002012
645501223353451351
72645436364210522
oct314125363207563
954607457204034
1014030245531507
11451a214920117
1216a71a4a10b57
137aa07b15585a
143670d334c4b9
15194e5b3771a7
hexcc2abcd0f73

14030245531507 has 2 divisors, whose sum is σ = 14030245531508. Its totient is φ = 14030245531506.

The previous prime is 14030245531501. The next prime is 14030245531513. The reversal of 14030245531507 is 70513554203041.

It is a balanced prime because it is at equal distance from previous prime (14030245531501) and next prime (14030245531513).

It is an emirp because it is prime and its reverse (70513554203041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14030245531507 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14030245531507.

It is not a weakly prime, because it can be changed into another prime (14030245531501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7015122765753 + 7015122765754.

It is an arithmetic number, because the mean of its divisors is an integer number (7015122765754).

Almost surely, 214030245531507 is an apocalyptic number.

14030245531507 is a deficient number, since it is larger than the sum of its proper divisors (1).

14030245531507 is an equidigital number, since it uses as much as digits as its factorization.

14030245531507 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252000, while the sum is 40.

Adding to 14030245531507 its reverse (70513554203041), we get a palindrome (84543799734548).

The spelling of 14030245531507 in words is "fourteen trillion, thirty billion, two hundred forty-five million, five hundred thirty-one thousand, five hundred seven".