Base | Representation |
---|---|
bin | 10100011010101111111… |
… | …111011100100111110001 |
3 | 11222010200021201221102202 |
4 | 110122233333130213301 |
5 | 140442033131433401 |
6 | 2552325235152545 |
7 | 203241265035356 |
oct | 24325777344761 |
9 | 4863607657382 |
10 | 1403111983601 |
11 | 4a1069154669 |
12 | 1a7b23445755 |
13 | a240b5695a3 |
14 | 4bca7a4262d |
15 | 2677147406b |
hex | 146affdc9f1 |
1403111983601 has 2 divisors, whose sum is σ = 1403111983602. Its totient is φ = 1403111983600.
The previous prime is 1403111983589. The next prime is 1403111983627. The reversal of 1403111983601 is 1063891113041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 958254999025 + 444856984576 = 978905^2 + 666976^2 .
It is a cyclic number.
It is not a de Polignac number, because 1403111983601 - 230 = 1402038241777 is a prime.
It is not a weakly prime, because it can be changed into another prime (1400111983601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701555991800 + 701555991801.
It is an arithmetic number, because the mean of its divisors is an integer number (701555991801).
Almost surely, 21403111983601 is an apocalyptic number.
It is an amenable number.
1403111983601 is a deficient number, since it is larger than the sum of its proper divisors (1).
1403111983601 is an equidigital number, since it uses as much as digits as its factorization.
1403111983601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 38.
The spelling of 1403111983601 in words is "one trillion, four hundred three billion, one hundred eleven million, nine hundred eighty-three thousand, six hundred one".
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